12x2=4x(1+3x)-16

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Solution for 12x2=4x(1+3x)-16 equation: 



12x^2=4x(1+3x)-16

We move all terms to the left:

12x^2-(4x(1+3x)-16)=0

We add all the numbers together, and all the variables

12x^2-(4x(3x+1)-16)=0



We calculate terms in parentheses: -(4x(3x+1)-16), so:

4x(3x+1)-16

We multiply parentheses

12x^2+4x-16

Back to the equation:

-(12x^2+4x-16)



We get rid of parentheses

12x^2-12x^2-4x+16=0

We add all the numbers together, and all the variables

-4x+16=0

We move all terms containing x to the left, all other terms to the right

-4x=-16

x=-16/-4

x=+4

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