12x=(x+3)(x+3)

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Solution for 12x=(x+3)(x+3) equation: 



12x=(x+3)(x+3)

We move all terms to the left:

12x-((x+3)(x+3))=0

We multiply parentheses ..

-((+x^2+3x+3x+9))+12x=0



We calculate terms in parentheses: -((+x^2+3x+3x+9)), so:

(+x^2+3x+3x+9)

We get rid of parentheses

x^2+3x+3x+9

We add all the numbers together, and all the variables

x^2+6x+9

Back to the equation:

-(x^2+6x+9)



We add all the numbers together, and all the variables

12x-(x^2+6x+9)=0

We get rid of parentheses

-x^2+12x-6x-9=0

We add all the numbers together, and all the variables

-1x^2+6x-9=0

a = -1; b = 6; c = -9;
Δ = b2-4ac
Δ = 62-4·(-1)·(-9)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-6}{-2}=+3$

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