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12x=20x(2)
We move all terms to the left:
12x-(20x(2))=0
determiningTheFunctionDomain 12x-20x2=0
We add all the numbers together, and all the variables
-20x^2+12x=0
a = -20; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-20)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-20}=\frac{-24}{-40} =3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-20}=\frac{0}{-40} =0 $
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