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12x=3(5+4x-15
We move all terms to the left:
12x-(3(5+4x-15)=0
We add all the numbers together, and all the variables
12x-(3(4x-10)=0
We calculate terms in parentheses: -(3(4x-10), so:
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| 2x-31=9 | | 46=x-7 | | 5u-14=13 | | r/8+29=37 | | a-14=-32 | | (5x)=(5x+30) | | 3b+4=-14 | | r-67/4=5 | | -(-6x-3)=17 | | 0.8(10x+16)=3.9(0.2x+5) | | 7-3x=5-6x | | 35=v/3+15 | | -4(20-2x)=12(x-6.5) | | 0.3x+2=0.4x-0.5 | | -5(3x+4)=-170 | | w/4+11=17 | | -2x+-4=2x+12 | | 3x+9-2x=-12-5x | | 3(4x-2)-5x=6-7(-x-2) | | 2.61x+81=6.8121+9x | | 8(x+5)=x+21 | | 16x=16x+8 | | 7(x+5)=x+21 | | 2/3c-14=-20 | | 6(x+5)=x+21 | | 2x+4x+40-x=50 | | Y-x2-5=0 | | x-52=2x | | 50+3x=20+5x | | 8−3w=5 | | 2x+2=6x-15 | | (x-2)=1/4(8x-12) |