12y+(3y-2)=-2

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Solution for 12y+(3y-2)=-2 equation: 



12y+(3y-2)=-2

We move all terms to the left:

12y+(3y-2)-(-2)=0

We add all the numbers together, and all the variables

12y+(3y-2)+2=0

We get rid of parentheses

12y+3y-2+2=0

We add all the numbers together, and all the variables

15y=0

y=0/15

y=0

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