12y+12+4=4(3y+4)

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Solution for 12y+12+4=4(3y+4) equation: 



12y+12+4=4(3y+4)

We move all terms to the left:

12y+12+4-(4(3y+4))=0

We add all the numbers together, and all the variables

12y-(4(3y+4))+16=0



We calculate terms in parentheses: -(4(3y+4)), so:

4(3y+4)

We multiply parentheses

12y+16

Back to the equation:

-(12y+16)



We get rid of parentheses

12y-12y-16+16=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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