12y+28=48

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Solution for 12y+28=48 equation: 



12y+28=48

We move all terms to the left:

12y+28-(48)=0

We add all the numbers together, and all the variables

12y-20=0

We move all terms containing y to the left, all other terms to the right

12y=20

y=20/12

y=1+2/3

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