12y+4=4(3y+1)

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Solution for 12y+4=4(3y+1) equation:


Simplifying
12y + 4 = 4(3y + 1)

Reorder the terms:
4 + 12y = 4(3y + 1)

Reorder the terms:
4 + 12y = 4(1 + 3y)
4 + 12y = (1 * 4 + 3y * 4)
4 + 12y = (4 + 12y)

Add '-4' to each side of the equation.
4 + -4 + 12y = 4 + -4 + 12y

Combine like terms: 4 + -4 = 0
0 + 12y = 4 + -4 + 12y
12y = 4 + -4 + 12y

Combine like terms: 4 + -4 = 0
12y = 0 + 12y
12y = 12y

Add '-12y' to each side of the equation.
12y + -12y = 12y + -12y

Combine like terms: 12y + -12y = 0
0 = 12y + -12y

Combine like terms: 12y + -12y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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