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12y+6=3(4y+1)
We move all terms to the left:
12y+6-(3(4y+1))=0
We calculate terms in parentheses: -(3(4y+1)), so:We get rid of parentheses
3(4y+1)
We multiply parentheses
12y+3
Back to the equation:
-(12y+3)
12y-12y-3+6=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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