12y+6=6(2y+1)0

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Solution for 12y+6=6(2y+1)0 equation: 



12y+6=6(2y+1)0

We move all terms to the left:

12y+6-(6(2y+1)0)=0



We calculate terms in parentheses: -(6(2y+1)0), so:

6(2y+1)0

We multiply parentheses

12y+6

Back to the equation:

-(12y+6)



We get rid of parentheses

12y-12y-6+6=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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