12y+6=6(2y-3)+24

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Solution for 12y+6=6(2y-3)+24 equation:



12y+6=6(2y-3)+24
We move all terms to the left:
12y+6-(6(2y-3)+24)=0
We calculate terms in parentheses: -(6(2y-3)+24), so:
6(2y-3)+24
We multiply parentheses
12y-18+24
We add all the numbers together, and all the variables
12y+6
Back to the equation:
-(12y+6)
We get rid of parentheses
12y-12y-6+6=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0

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