12y+8/2=3(1-2y)+y

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Solution for 12y+8/2=3(1-2y)+y equation: 



12y+8/2=3(1-2y)+y

We move all terms to the left:

12y+8/2-(3(1-2y)+y)=0

We add all the numbers together, and all the variables

12y-(3(-2y+1)+y)+8/2=0

We add all the numbers together, and all the variables

12y-(3(-2y+1)+y)+4=0



We calculate terms in parentheses: -(3(-2y+1)+y), so:

3(-2y+1)+y

We add all the numbers together, and all the variables

y+3(-2y+1)

We multiply parentheses

y-6y+3

We add all the numbers together, and all the variables

-5y+3

Back to the equation:

-(-5y+3)



We get rid of parentheses

12y+5y-3+4=0

We add all the numbers together, and all the variables

17y+1=0

We move all terms containing y to the left, all other terms to the right

17y=-1

y=-1/17

y=-1/17

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