12y-10=2(6y-5)

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Solution for 12y-10=2(6y-5) equation:



12y-10=2(6y-5)
We move all terms to the left:
12y-10-(2(6y-5))=0
We calculate terms in parentheses: -(2(6y-5)), so:
2(6y-5)
We multiply parentheses
12y-10
Back to the equation:
-(12y-10)
We get rid of parentheses
12y-12y+10-10=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0

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