12y-10=2(6y-5)

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Solution for 12y-10=2(6y-5) equation: 



12y-10=2(6y-5)

We move all terms to the left:

12y-10-(2(6y-5))=0



We calculate terms in parentheses: -(2(6y-5)), so:

2(6y-5)

We multiply parentheses

12y-10

Back to the equation:

-(12y-10)



We get rid of parentheses

12y-12y+10-10=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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