12y-28=4(3y-7)

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Solution for 12y-28=4(3y-7) equation: 



12y-28=4(3y-7)

We move all terms to the left:

12y-28-(4(3y-7))=0



We calculate terms in parentheses: -(4(3y-7)), so:

4(3y-7)

We multiply parentheses

12y-28

Back to the equation:

-(12y-28)



We get rid of parentheses

12y-12y+28-28=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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