12y-3=10y+(1/2)

Solution for 12y-3=10y+(1/2) equation:

12y-3=10y+(1/2)

We move all terms to the left:

12y-3-(10y+(1/2))=0

We add all the numbers together, and all the variables

12y-(10y+(+1/2))-3=0

We multiply all the terms by the denominator


12y*2))-(10y+(+1-3*2))=0

We add all the numbers together, and all the variables

12y*2))-(10y+(-5))=0

We add all the numbers together, and all the variables

12y*2))-(10y+(=0

Wy multiply elements

24y^2=0

a = 24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·24·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{48}=0$