12y-4(1+y)=2(2y-2)-20

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Solution for 12y-4(1+y)=2(2y-2)-20 equation: 



12y-4(1+y)=2(2y-2)-20

We move all terms to the left:

12y-4(1+y)-(2(2y-2)-20)=0

We add all the numbers together, and all the variables

12y-4(y+1)-(2(2y-2)-20)=0

We multiply parentheses

12y-4y-(2(2y-2)-20)-4=0



We calculate terms in parentheses: -(2(2y-2)-20), so:

2(2y-2)-20

We multiply parentheses

4y-4-20

We add all the numbers together, and all the variables

4y-24

Back to the equation:

-(4y-24)



We add all the numbers together, and all the variables

8y-(4y-24)-4=0

We get rid of parentheses

8y-4y+24-4=0

We add all the numbers together, and all the variables

4y+20=0

We move all terms containing y to the left, all other terms to the right

4y=-20

y=-20/4

y=-5

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