12y-48(17+9y)=3y-12

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Solution for 12y-48(17+9y)=3y-12 equation: 



12y-48(17+9y)=3y-12

We move all terms to the left:

12y-48(17+9y)-(3y-12)=0

We add all the numbers together, and all the variables

12y-48(9y+17)-(3y-12)=0

We multiply parentheses

12y-432y-(3y-12)-816=0

We get rid of parentheses

12y-432y-3y+12-816=0

We add all the numbers together, and all the variables

-423y-804=0

We move all terms containing y to the left, all other terms to the right

-423y=804

y=804/-423

y=-1+127/141

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