12y-5(3-6y)=30+6(5y-5)

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Solution for 12y-5(3-6y)=30+6(5y-5) equation: 



12y-5(3-6y)=30+6(5y-5)

We move all terms to the left:

12y-5(3-6y)-(30+6(5y-5))=0

We add all the numbers together, and all the variables

12y-5(-6y+3)-(30+6(5y-5))=0

We multiply parentheses

12y+30y-(30+6(5y-5))-15=0



We calculate terms in parentheses: -(30+6(5y-5)), so:

30+6(5y-5)

determiningTheFunctionDomain
6(5y-5)+30

We multiply parentheses

30y-30+30

We add all the numbers together, and all the variables

30y

Back to the equation:

-(30y)



We add all the numbers together, and all the variables

12y-15=0

We move all terms containing y to the left, all other terms to the right

12y=15

y=15/12

y=1+1/4

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