12y-96+20y=4y-1(40)

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Solution for 12y-96+20y=4y-1(40) equation: 



12y-96+20y=4y-1(40)

We move all terms to the left:

12y-96+20y-(4y-1(40))=0

We add all the numbers together, and all the variables

32y-(4y-140)-96=0

We get rid of parentheses

32y-4y+140-96=0

We add all the numbers together, and all the variables

28y+44=0

We move all terms containing y to the left, all other terms to the right

28y=-44

y=-44/28

y=-1+4/7

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