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12y^2+7y-1=0
a = 12; b = 7; c = -1;
Δ = b2-4ac
Δ = 72-4·12·(-1)
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{97}}{2*12}=\frac{-7-\sqrt{97}}{24} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{97}}{2*12}=\frac{-7+\sqrt{97}}{24} $
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