12y2-29y+15=0

Solution for 12y2-29y+15=0 equation:

12y^2-29y+15=0

a = 12; b = -29; c = +15;
Δ = b2-4ac
Δ = -292-4·12·15
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-11}{2*12}=\frac{18}{24}
=3/4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+11}{2*12}=\frac{40}{24}
=1+2/3
$