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12y=3(4y+2)-6
We move all terms to the left:
12y-(3(4y+2)-6)=0
We calculate terms in parentheses: -(3(4y+2)-6), so:We add all the numbers together, and all the variables
3(4y+2)-6
We multiply parentheses
12y+6-6
We add all the numbers together, and all the variables
12y
Back to the equation:
-(12y)
=0
y=0/1
y=0
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