12z+2(z-3)=7+5(2z-1)

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Solution for 12z+2(z-3)=7+5(2z-1) equation:


Simplifying
12z + 2(z + -3) = 7 + 5(2z + -1)

Reorder the terms:
12z + 2(-3 + z) = 7 + 5(2z + -1)
12z + (-3 * 2 + z * 2) = 7 + 5(2z + -1)
12z + (-6 + 2z) = 7 + 5(2z + -1)

Reorder the terms:
-6 + 12z + 2z = 7 + 5(2z + -1)

Combine like terms: 12z + 2z = 14z
-6 + 14z = 7 + 5(2z + -1)

Reorder the terms:
-6 + 14z = 7 + 5(-1 + 2z)
-6 + 14z = 7 + (-1 * 5 + 2z * 5)
-6 + 14z = 7 + (-5 + 10z)

Combine like terms: 7 + -5 = 2
-6 + 14z = 2 + 10z

Solving
-6 + 14z = 2 + 10z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-10z' to each side of the equation.
-6 + 14z + -10z = 2 + 10z + -10z

Combine like terms: 14z + -10z = 4z
-6 + 4z = 2 + 10z + -10z

Combine like terms: 10z + -10z = 0
-6 + 4z = 2 + 0
-6 + 4z = 2

Add '6' to each side of the equation.
-6 + 6 + 4z = 2 + 6

Combine like terms: -6 + 6 = 0
0 + 4z = 2 + 6
4z = 2 + 6

Combine like terms: 2 + 6 = 8
4z = 8

Divide each side by '4'.
z = 2

Simplifying
z = 2

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