12z+2=28

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Solution for 12z+2=28 equation: 



12z+2=28

We move all terms to the left:

12z+2-(28)=0

We add all the numbers together, and all the variables

12z-26=0

We move all terms containing z to the left, all other terms to the right

12z=26

z=26/12

z=2+1/6

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