12z+44=3z+80

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Solution for 12z+44=3z+80 equation: 



12z+44=3z+80

We move all terms to the left:

12z+44-(3z+80)=0

We get rid of parentheses

12z-3z-80+44=0

We add all the numbers together, and all the variables

9z-36=0

We move all terms containing z to the left, all other terms to the right

9z=36

z=36/9

z=4

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