12z-(4z+6)=62

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Solution for 12z-(4z+6)=62 equation:



12z-(4z+6)=62
We move all terms to the left:
12z-(4z+6)-(62)=0
We get rid of parentheses
12z-4z-6-62=0
We add all the numbers together, and all the variables
8z-68=0
We move all terms containing z to the left, all other terms to the right
8z=68
z=68/8
z=8+1/2

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