12z-20=28

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Solution for 12z-20=28 equation: 



12z-20=28

We move all terms to the left:

12z-20-(28)=0

We add all the numbers together, and all the variables

12z-48=0

We move all terms containing z to the left, all other terms to the right

12z=48

z=48/12

z=4

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