12z-48=10z/2

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Solution for 12z-48=10z/2 equation: 



12z-48=10z/2

We move all terms to the left:

12z-48-(10z/2)=0

We add all the numbers together, and all the variables

12z-(+10z/2)-48=0

We get rid of parentheses

12z-10z/2-48=0

We multiply all the terms by the denominator


12z*2-10z-48*2=0

We add all the numbers together, and all the variables

-10z+12z*2-96=0

Wy multiply elements

-10z+24z-96=0

We add all the numbers together, and all the variables

14z-96=0

We move all terms containing z to the left, all other terms to the right

14z=96

z=96/14

z=6+6/7

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