12z-48=10z/20

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Solution for 12z-48=10z/20 equation:



12z-48=10z/20
We move all terms to the left:
12z-48-(10z/20)=0
We add all the numbers together, and all the variables
12z-(+10z/20)-48=0
We get rid of parentheses
12z-10z/20-48=0
We multiply all the terms by the denominator
12z*20-10z-48*20=0
We add all the numbers together, and all the variables
-10z+12z*20-960=0
Wy multiply elements
-10z+240z-960=0
We add all the numbers together, and all the variables
230z-960=0
We move all terms containing z to the left, all other terms to the right
230z=960
z=960/230
z=4+4/23

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