12z-6+15=27z-5

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Solution for 12z-6+15=27z-5 equation: 



12z-6+15=27z-5

We move all terms to the left:

12z-6+15-(27z-5)=0

We add all the numbers together, and all the variables

12z-(27z-5)+9=0

We get rid of parentheses

12z-27z+5+9=0

We add all the numbers together, and all the variables

-15z+14=0

We move all terms containing z to the left, all other terms to the right

-15z=-14

z=-14/-15

z=14/15

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