13(1+3b)=12b-95

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Solution for 13(1+3b)=12b-95 equation:


Simplifying
13(1 + 3b) = 12b + -95
(1 * 13 + 3b * 13) = 12b + -95
(13 + 39b) = 12b + -95

Reorder the terms:
13 + 39b = -95 + 12b

Solving
13 + 39b = -95 + 12b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-12b' to each side of the equation.
13 + 39b + -12b = -95 + 12b + -12b

Combine like terms: 39b + -12b = 27b
13 + 27b = -95 + 12b + -12b

Combine like terms: 12b + -12b = 0
13 + 27b = -95 + 0
13 + 27b = -95

Add '-13' to each side of the equation.
13 + -13 + 27b = -95 + -13

Combine like terms: 13 + -13 = 0
0 + 27b = -95 + -13
27b = -95 + -13

Combine like terms: -95 + -13 = -108
27b = -108

Divide each side by '27'.
b = -4

Simplifying
b = -4

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