13(2c+2)=2(c+2)+3c

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Solution for 13(2c+2)=2(c+2)+3c equation:


Simplifying
13(2c + 2) = 2(c + 2) + 3c

Reorder the terms:
13(2 + 2c) = 2(c + 2) + 3c
(2 * 13 + 2c * 13) = 2(c + 2) + 3c
(26 + 26c) = 2(c + 2) + 3c

Reorder the terms:
26 + 26c = 2(2 + c) + 3c
26 + 26c = (2 * 2 + c * 2) + 3c
26 + 26c = (4 + 2c) + 3c

Combine like terms: 2c + 3c = 5c
26 + 26c = 4 + 5c

Solving
26 + 26c = 4 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
26 + 26c + -5c = 4 + 5c + -5c

Combine like terms: 26c + -5c = 21c
26 + 21c = 4 + 5c + -5c

Combine like terms: 5c + -5c = 0
26 + 21c = 4 + 0
26 + 21c = 4

Add '-26' to each side of the equation.
26 + -26 + 21c = 4 + -26

Combine like terms: 26 + -26 = 0
0 + 21c = 4 + -26
21c = 4 + -26

Combine like terms: 4 + -26 = -22
21c = -22

Divide each side by '21'.
c = -1.047619048

Simplifying
c = -1.047619048

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