13(2x+5)=11(3x+4)

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Solution for 13(2x+5)=11(3x+4) equation: 



13(2x+5)=11(3x+4)

We move all terms to the left:

13(2x+5)-(11(3x+4))=0

We multiply parentheses

26x-(11(3x+4))+65=0



We calculate terms in parentheses: -(11(3x+4)), so:

11(3x+4)

We multiply parentheses

33x+44

Back to the equation:

-(33x+44)



We get rid of parentheses

26x-33x-44+65=0

We add all the numbers together, and all the variables

-7x+21=0

We move all terms containing x to the left, all other terms to the right

-7x=-21

x=-21/-7

x=+3

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