13(3c+2)=2(c+2)+4c

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Solution for 13(3c+2)=2(c+2)+4c equation: 



13(3c+2)=2(c+2)+4c

We move all terms to the left:

13(3c+2)-(2(c+2)+4c)=0

We multiply parentheses

39c-(2(c+2)+4c)+26=0



We calculate terms in parentheses: -(2(c+2)+4c), so:

2(c+2)+4c

We add all the numbers together, and all the variables

4c+2(c+2)

We multiply parentheses

4c+2c+4

We add all the numbers together, and all the variables

6c+4

Back to the equation:

-(6c+4)



We get rid of parentheses

39c-6c-4+26=0

We add all the numbers together, and all the variables

33c+22=0

We move all terms containing c to the left, all other terms to the right

33c=-22

c=-22/33

c=-2/3

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