13(4c-1)-18=50c+13

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Solution for 13(4c-1)-18=50c+13 equation: 



13(4c-1)-18=50c+13

We move all terms to the left:

13(4c-1)-18-(50c+13)=0

We multiply parentheses

52c-(50c+13)-13-18=0

We get rid of parentheses

52c-50c-13-13-18=0

We add all the numbers together, and all the variables

2c-44=0

We move all terms containing c to the left, all other terms to the right

2c=44

c=44/2

c=22

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