13(d+2)+13d=1

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Solution for 13(d+2)+13d=1 equation: 



13(d+2)+13d=1

We move all terms to the left:

13(d+2)+13d-(1)=0

We add all the numbers together, and all the variables

13d+13(d+2)-1=0

We multiply parentheses

13d+13d+26-1=0

We add all the numbers together, and all the variables

26d+25=0

We move all terms containing d to the left, all other terms to the right

26d=-25

d=-25/26

d=-25/26

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