13(n+1)+2=16(3n-5)

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Solution for 13(n+1)+2=16(3n-5) equation: 



13(n+1)+2=16(3n-5)

We move all terms to the left:

13(n+1)+2-(16(3n-5))=0

We multiply parentheses

13n-(16(3n-5))+13+2=0



We calculate terms in parentheses: -(16(3n-5)), so:

16(3n-5)

We multiply parentheses

48n-80

Back to the equation:

-(48n-80)



We add all the numbers together, and all the variables

13n-(48n-80)+15=0

We get rid of parentheses

13n-48n+80+15=0

We add all the numbers together, and all the variables

-35n+95=0

We move all terms containing n to the left, all other terms to the right

-35n=-95

n=-95/-35

n=2+5/7

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