13(s+4)=4(s-11)+51

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Solution for 13(s+4)=4(s-11)+51 equation: 



13(s+4)=4(s-11)+51

We move all terms to the left:

13(s+4)-(4(s-11)+51)=0

We multiply parentheses

13s-(4(s-11)+51)+52=0



We calculate terms in parentheses: -(4(s-11)+51), so:

4(s-11)+51

We multiply parentheses

4s-44+51

We add all the numbers together, and all the variables

4s+7

Back to the equation:

-(4s+7)



We get rid of parentheses

13s-4s-7+52=0

We add all the numbers together, and all the variables

9s+45=0

We move all terms containing s to the left, all other terms to the right

9s=-45

s=-45/9

s=-5

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