13(t+1)+3(2+4t)=38

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Solution for 13(t+1)+3(2+4t)=38 equation:


Simplifying
13(t + 1) + 3(2 + 4t) = 38

Reorder the terms:
13(1 + t) + 3(2 + 4t) = 38
(1 * 13 + t * 13) + 3(2 + 4t) = 38
(13 + 13t) + 3(2 + 4t) = 38
13 + 13t + (2 * 3 + 4t * 3) = 38
13 + 13t + (6 + 12t) = 38

Reorder the terms:
13 + 6 + 13t + 12t = 38

Combine like terms: 13 + 6 = 19
19 + 13t + 12t = 38

Combine like terms: 13t + 12t = 25t
19 + 25t = 38

Solving
19 + 25t = 38

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-19' to each side of the equation.
19 + -19 + 25t = 38 + -19

Combine like terms: 19 + -19 = 0
0 + 25t = 38 + -19
25t = 38 + -19

Combine like terms: 38 + -19 = 19
25t = 19

Divide each side by '25'.
t = 0.76

Simplifying
t = 0.76

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