13(t+1)-3(2+4t)=48

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Solution for 13(t+1)-3(2+4t)=48 equation:


Simplifying
13(t + 1) + -3(2 + 4t) = 48

Reorder the terms:
13(1 + t) + -3(2 + 4t) = 48
(1 * 13 + t * 13) + -3(2 + 4t) = 48
(13 + 13t) + -3(2 + 4t) = 48
13 + 13t + (2 * -3 + 4t * -3) = 48
13 + 13t + (-6 + -12t) = 48

Reorder the terms:
13 + -6 + 13t + -12t = 48

Combine like terms: 13 + -6 = 7
7 + 13t + -12t = 48

Combine like terms: 13t + -12t = 1t
7 + 1t = 48

Solving
7 + 1t = 48

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + 1t = 48 + -7

Combine like terms: 7 + -7 = 0
0 + 1t = 48 + -7
1t = 48 + -7

Combine like terms: 48 + -7 = 41
1t = 41

Divide each side by '1'.
t = 41

Simplifying
t = 41

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