13(t+1)-3(2=4t)=38

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Solution for 13(t+1)-3(2=4t)=38 equation:



13(t+1)-3(2=4t)=38
We move all terms to the left:
13(t+1)-3(2-(4t))=0
We add all the numbers together, and all the variables
13(t+1)-3(-4t+2)=0
We multiply parentheses
13t+12t+13-6=0
We add all the numbers together, and all the variables
25t+7=0
We move all terms containing t to the left, all other terms to the right
25t=-7
t=-7/25
t=-7/25

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