13(t+4)=2(t-10)-27

Solution for 13(t+4)=2(t-10)-27 equation:

Simplifying
13(t + 4) = 2(t + -10) + -27

Reorder the terms:
13(4 + t) = 2(t + -10) + -27
(4 * 13 + t * 13) = 2(t + -10) + -27
(52 + 13t) = 2(t + -10) + -27

Reorder the terms:
52 + 13t = 2(-10 + t) + -27
52 + 13t = (-10 * 2 + t * 2) + -27
52 + 13t = (-20 + 2t) + -27

Reorder the terms:
52 + 13t = -20 + -27 + 2t

Combine like terms: -20 + -27 = -47
52 + 13t = -47 + 2t

Solving
52 + 13t = -47 + 2t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2t' to each side of the equation.
52 + 13t + -2t = -47 + 2t + -2t

Combine like terms: 13t + -2t = 11t
52 + 11t = -47 + 2t + -2t

Combine like terms: 2t + -2t = 0
52 + 11t = -47 + 0
52 + 11t = -47

Add '-52' to each side of the equation.
52 + -52 + 11t = -47 + -52

Combine like terms: 52 + -52 = 0
0 + 11t = -47 + -52
11t = -47 + -52

Combine like terms: -47 + -52 = -99
11t = -99

Divide each side by '11'.
t = -9

Simplifying
t = -9