13(x+3)-4(x-3)=4(x-2)+4(x-1)

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Solution for 13(x+3)-4(x-3)=4(x-2)+4(x-1) equation:


13(x+3)-4(x-3)=4(x-2)+4(x-1)

We simplify the equation to the form, which is simple to understand 
13(x+3)-4(x-3)=4(x-2)+4(x-1)

Reorder the terms in parentheses
+(+13x+39)-4*(x-3)=4*(x-2)+4*(x-1)

Remove unnecessary parentheses
+13x+39-4+*(+x-3+)=+4+*(+x-2+)+4+*(+x-1+)

Reorder the terms in parentheses
+13x+39+(-4x+12)=4*(x-2)+4*(x-1)

Remove unnecessary parentheses
+13x+39-4x+12=+4+*(+x-2+)+4+*(+x-1+)

Reorder the terms in parentheses
+13x+39-4x+12=+(+4x-8)+4*(x-1)

Remove unnecessary parentheses
+13x+39-4x+12=+4x-8+4+*(+x-1+)

Reorder the terms in parentheses
+13x+39-4x+12=+4x-8+(+4x-4)

Remove unnecessary parentheses
+13x+39-4x+12=+4x-8+4x-4

We move all terms containing x to the left and all other terms to the right. 
+13x-4x-4x-4x=-8-4-39-12

We simplify left and right side of the equation. 
+1x=-63

We divide both sides of the equation by 1 to get x. 
x=-63

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