13(x-1)=5(x-2)+(3x+7)

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Solution for 13(x-1)=5(x-2)+(3x+7) equation:



13(x-1)=5(x-2)+(3x+7)
We move all terms to the left:
13(x-1)-(5(x-2)+(3x+7))=0
We multiply parentheses
13x-(5(x-2)+(3x+7))-13=0
We calculate terms in parentheses: -(5(x-2)+(3x+7)), so:
5(x-2)+(3x+7)
We multiply parentheses
5x+(3x+7)-10
We get rid of parentheses
5x+3x+7-10
We add all the numbers together, and all the variables
8x-3
Back to the equation:
-(8x-3)
We get rid of parentheses
13x-8x+3-13=0
We add all the numbers together, and all the variables
5x-10=0
We move all terms containing x to the left, all other terms to the right
5x=10
x=10/5
x=2

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