13(x-5)+6=x-(9-2x)

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Solution for 13(x-5)+6=x-(9-2x) equation: 



13(x-5)+6=x-(9-2x)

We move all terms to the left:

13(x-5)+6-(x-(9-2x))=0

We add all the numbers together, and all the variables

13(x-5)-(x-(-2x+9))+6=0

We multiply parentheses

13x-(x-(-2x+9))-65+6=0



We calculate terms in parentheses: -(x-(-2x+9)), so:

x-(-2x+9)

We get rid of parentheses

x+2x-9

We add all the numbers together, and all the variables

3x-9

Back to the equation:

-(3x-9)



We add all the numbers together, and all the variables

13x-(3x-9)-59=0

We get rid of parentheses

13x-3x+9-59=0

We add all the numbers together, and all the variables

10x-50=0

We move all terms containing x to the left, all other terms to the right

10x=50

x=50/10

x=5

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