13(y+1)+6=3y-1

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Solution for 13(y+1)+6=3y-1 equation: 


Simplifying
13(y + 1) + 6 = 3y + -1

Reorder the terms:
13(1 + y) + 6 = 3y + -1
(1 * 13 + y * 13) + 6 = 3y + -1
(13 + 13y) + 6 = 3y + -1

Reorder the terms:
13 + 6 + 13y = 3y + -1

Combine like terms: 13 + 6 = 19
19 + 13y = 3y + -1

Reorder the terms:
19 + 13y = -1 + 3y

Solving
19 + 13y = -1 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
19 + 13y + -3y = -1 + 3y + -3y

Combine like terms: 13y + -3y = 10y
19 + 10y = -1 + 3y + -3y

Combine like terms: 3y + -3y = 0
19 + 10y = -1 + 0
19 + 10y = -1

Add '-19' to each side of the equation.
19 + -19 + 10y = -1 + -19

Combine like terms: 19 + -19 = 0
0 + 10y = -1 + -19
10y = -1 + -19

Combine like terms: -1 + -19 = -20
10y = -20

Divide each side by '10'.
y = -2

Simplifying
y = -2

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