13(y+3)=13y+3913(y+3)=13y+39

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Solution for 13(y+3)=13y+3913(y+3)=13y+39 equation:



13(y+3)=13y+3913(y+3)=13y+39
We move all terms to the left:
13(y+3)-(13y+3913(y+3))=0
We multiply parentheses
13y-(13y+3913(y+3))+39=0
We calculate terms in parentheses: -(13y+3913(y+3)), so:
13y+3913(y+3)
We multiply parentheses
13y+3913y+11739
We add all the numbers together, and all the variables
3926y+11739
Back to the equation:
-(3926y+11739)
We get rid of parentheses
13y-3926y-11739+39=0
We add all the numbers together, and all the variables
-3913y-11700=0
We move all terms containing y to the left, all other terms to the right
-3913y=11700
y=11700/-3913
y=-2+298/301

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