13(y+3)=13y+3913(y+3)=13y+3913

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Solution for 13(y+3)=13y+3913(y+3)=13y+3913 equation: 



13(y+3)=13y+3913(y+3)=13y+3913

We move all terms to the left:

13(y+3)-(13y+3913(y+3))=0

We multiply parentheses

13y-(13y+3913(y+3))+39=0



We calculate terms in parentheses: -(13y+3913(y+3)), so:

13y+3913(y+3)

We multiply parentheses

13y+3913y+11739

We add all the numbers together, and all the variables

3926y+11739

Back to the equation:

-(3926y+11739)



We get rid of parentheses

13y-3926y-11739+39=0

We add all the numbers together, and all the variables

-3913y-11700=0

We move all terms containing y to the left, all other terms to the right

-3913y=11700

y=11700/-3913

y=-2+298/301

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