13(y-3)=3(4y+2)-45

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Solution for 13(y-3)=3(4y+2)-45 equation: 



13(y-3)=3(4y+2)-45

We move all terms to the left:

13(y-3)-(3(4y+2)-45)=0

We multiply parentheses

13y-(3(4y+2)-45)-39=0



We calculate terms in parentheses: -(3(4y+2)-45), so:

3(4y+2)-45

We multiply parentheses

12y+6-45

We add all the numbers together, and all the variables

12y-39

Back to the equation:

-(12y-39)



We get rid of parentheses

13y-12y+39-39=0

We add all the numbers together, and all the variables

y=0

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