13(y-4)-3(y-9)=5(3y+4)

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Solution for 13(y-4)-3(y-9)=5(3y+4) equation: 



13(y-4)-3(y-9)=5(3y+4)

We move all terms to the left:

13(y-4)-3(y-9)-(5(3y+4))=0

We multiply parentheses

13y-3y-(5(3y+4))-52+27=0



We calculate terms in parentheses: -(5(3y+4)), so:

5(3y+4)

We multiply parentheses

15y+20

Back to the equation:

-(15y+20)



We add all the numbers together, and all the variables

10y-(15y+20)-25=0

We get rid of parentheses

10y-15y-20-25=0

We add all the numbers together, and all the variables

-5y-45=0

We move all terms containing y to the left, all other terms to the right

-5y=45

y=45/-5

y=-9

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